(X-4)^2=(2X-5)*(10-3x)

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Solution for (X-4)^2=(2X-5)*(10-3x) equation: 



(X-4)^2=(2X-5)(10-3X)

We move all terms to the left:

(X-4)^2-((2X-5)(10-3X))=0

We add all the numbers together, and all the variables

(X-4)^2-((2X-5)(-3X+10))=0

We multiply parentheses ..

-((-6X^2+20X+15X-50))+(X-4)^2=0



We calculate terms in parentheses: -((-6X^2+20X+15X-50)), so:

(-6X^2+20X+15X-50)

We get rid of parentheses

-6X^2+20X+15X-50

We add all the numbers together, and all the variables

-6X^2+35X-50

Back to the equation:

-(-6X^2+35X-50)



We get rid of parentheses

6X^2-35X+(X-4)^2+50=0

We move all terms containing X to the left, all other terms to the right

6X^2-35X+(X-4)^2=-50

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